Interesting take with the math, but in ‘55 you had a realistic chance of riding every ride. Your math for what a day would cost to ride every attraction in every park (2 parks in CA, 4 parks in FL) is an impossible feat to accomplish in a single day. If you did your math on a pet park basis you would have to come to the conclusion that the daily park prices are extremely high.
I agree with Sam. Based on their “Disney Math” & the availability of 90 attractions between 2 parks, you would have to complete 5.6 attractions/hr x 16 hrs (Disneyland is sometimes open from 8AM-Midnight). Of course, that is NOT figuring in time for meals, snacks, & restroom breaks. Even on a good day, I can’t imagine doing 90 attractions in 16 hrs!!! Nice try but your math is a bit Goofy”!!!
I agree with Sam and Karla (is this getting monotonous?) You say, “Well, to get that same value in 1955 on Disneyland’s original procedures and pricing, it would cost you ~$76 to have access to every single ride at Disneyland.”
However, when we visited Disneyland as small kids in the late 50’s and early 60’s, we certainly didn’t worry about going on every single ride. We bought a ticket book, rode some rides, visited the shops, had a picnic, and usually came home with a few tickets left in each book. So for the equivalent of maybe $35-50 today we had a wonderful time.
Not that I can complain about Disneyland’s prices — it’s their business and have all the visitors they can handle, I think. It’s a great place. But it does seem to have changed its price point over the years.
All three previous posts made the same point abut how ridiculous it is to use an ‘every ride’ measure, when that is not likely possible.
It’s like Disney marketing wanted to come up with a silly argument how they’re not really that expensive.
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